ftrace: Avoid potential division by zero in function_stat_show()
Check whether denominator expression x * (x - 1) * 1000 mod {2^32, 2^64}
produce zero and skip stddev computation in that case.
For now don't care about rec->counter * rec->counter overflow because
rec->time * rec->time overflow will likely happen earlier.
Cc: stable@vger.kernel.org
Cc: Wen Yang <wenyang@linux.alibaba.com>
Cc: Mark Rutland <mark.rutland@arm.com>
Cc: Mathieu Desnoyers <mathieu.desnoyers@efficios.com>
Link: https://lore.kernel.org/20250206090156.1561783-1-kniv@yandex-team.ru
Fixes: e31f7939c1
("ftrace: Avoid potential division by zero in function profiler")
Signed-off-by: Nikolay Kuratov <kniv@yandex-team.ru>
Signed-off-by: Steven Rostedt (Google) <rostedt@goodmis.org>
This commit is contained in:
parent
3908b6baf2
commit
a1a7eb89ca
1 changed files with 12 additions and 15 deletions
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@ -540,6 +540,7 @@ static int function_stat_show(struct seq_file *m, void *v)
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static struct trace_seq s;
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unsigned long long avg;
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unsigned long long stddev;
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unsigned long long stddev_denom;
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#endif
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guard(mutex)(&ftrace_profile_lock);
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@ -559,23 +560,19 @@ static int function_stat_show(struct seq_file *m, void *v)
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#ifdef CONFIG_FUNCTION_GRAPH_TRACER
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seq_puts(m, " ");
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/* Sample standard deviation (s^2) */
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if (rec->counter <= 1)
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stddev = 0;
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else {
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/*
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* Apply Welford's method:
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* s^2 = 1 / (n * (n-1)) * (n * \Sum (x_i)^2 - (\Sum x_i)^2)
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*/
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/*
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* Variance formula:
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* s^2 = 1 / (n * (n-1)) * (n * \Sum (x_i)^2 - (\Sum x_i)^2)
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* Maybe Welford's method is better here?
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* Divide only by 1000 for ns^2 -> us^2 conversion.
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* trace_print_graph_duration will divide by 1000 again.
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*/
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stddev = 0;
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stddev_denom = rec->counter * (rec->counter - 1) * 1000;
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if (stddev_denom) {
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stddev = rec->counter * rec->time_squared -
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rec->time * rec->time;
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/*
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* Divide only 1000 for ns^2 -> us^2 conversion.
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* trace_print_graph_duration will divide 1000 again.
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*/
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stddev = div64_ul(stddev,
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rec->counter * (rec->counter - 1) * 1000);
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stddev = div64_ul(stddev, stddev_denom);
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}
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trace_seq_init(&s);
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